Question

(cos²x/1-tanx)+(sin³x/sinx-cosx)​

Answer 1

Step-by-step explanation:

(cos^2x/1-tanx)+(sin^3x/sinx-cosx)

(cos^2x/1-sinx/cosx)+(sin^3x/sinx-cosx)

(cos^2x×cosx/cosx-sinx)+(sin^3x/sinx-cosx)

-cos^3x+sin^3x/sinx-cosx

(sinx-cosx)(sin^2x-cos^2x)/(sinx-cosx)=1