Question

(cos2x + 2sin²x)/cos²x.dx
Integrate the function

Answer 1

Given: The term (cos2x + 2sin²x)/cos²x.dx

To find: Integrate the function

Solution:

• Now we have given the function as (cos2x + 2sin²x)/cos²x dx

• Now using the formula of cos 2x, we get:

                (1 - 2 sin^2 x + 2 sin^2 x) / cos^2 x dx

• Now simplifying it, we get:

                1 / cos^2 x dx

                sec^2 x dx

                tan x + C

Answer:

           So the integration of (cos2x + 2sin²x)/cos²x.dx is tan x + C.