Math, asked by nikhilmpgowda, 1 year ago

Cos2x=cos60.cos30+sin60.sin30 find sin2x

Answers

Answered by advsanjaychandak
7

Answer:

Step-by-step explanation:

Cos60.cos30+sin60.sin30

1/2.√3/2+√3/2.1/2

√3/4+√3/4

2√3/4

√3/2=cos2x

Sin=√1-cos^2

Sin=√1-(√3/2)^2

√1-3/4

√1/4

Sin2x=1/2.

Hope you will get


nikhilmpgowda: Weather sin2x=45°
Answered by Anonymous
6
Heya

_______________________________

Cos ( A - B ) = Cos A × Cos B + Sin A × Sin B

_______________________________

Cos 2x = Cos ( 60 - 30 )

=>

Cos 2x = Cos 30

=>

2x = 30°

=>

So, Sin 2x = Sin ( 30° ) = 1/2

=>

Sin 2x = 1/2
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