cos2x/cosx integration is equal to
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Hey mate thanks for asking here is your solution
cos2x = 2cos^2(x) - 1
cos2x/cosx= [2cos^2(x) - 1]/ cosx =2cosx - secx
on integrating we'll get
= 2sinx + ln |secx + tanx| + C
cos2x = 2cos^2(x) - 1
cos2x/cosx= [2cos^2(x) - 1]/ cosx =2cosx - secx
on integrating we'll get
= 2sinx + ln |secx + tanx| + C
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