cos2x/cosx-snx = cosx+sinx proeve it
if anyine solve then answer
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Answer:
Step-by-step explanation:
Given ∣sinx+cosx∣=∣sinx∣+∣cosx∣
For 0≤x≤π/2
sinx+cosx=sinx+cosx
⇒0⩽x⩽π/2
For π/2⩽x⩽π,sinx>0cosx<0
LHS sinx−cosx>0x<3π/4
sinx−cosx<0x>3π/2
RHS : sinx+cosx
L.H.S
= RHS
For π⩽x<3π/2
LHS = ∣−sinx−cosx∣
RHS = ∣−sinx∣+∣−cosx∣
LHS = RHS ⇒π⩽x⩽3π/2
For 3π/2<x<2π
LHS :∣−sinx+cosx∣=∣cosx−sinx∣
RHS : ∣sinx∣+∣cosx∣
LHS
= RHS
⇒0⩽x⩽π/2 and π⩽x⩽3π/2
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