cos²x = sin(x-15), find x
pls give step by step explanation
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Step-by-step explanation:
-1 ≤ sin(x-15) ≤ 1
-1≤cos2x≤1
-1≤2cos²x-1≤1
-1+1≤2cos²x-1+1≤1+1
0≤2cos²x≤2
0/2≤2cos²x/2≤2/2
0≤cos²x≤1
The two solution of the equatioms are
-1≤sin(x-15)≤1 0≤cos²x≤1
Common solution is (0,1)
sin(x-15) is either in 1st or second quadrant
In first quadrant we qill not get any solution
In second quadrant we get
x=
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