cos2x-sin2x/sin2x+cos2x
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Hi !
cos² x - sin²x / sin²x + cos²x
We know that ,
sin²x + cos²x = 1
so,
cos²x - sin²x /1
we can write ,
sin²x = 1 - cos²x
hence,
cos²x - ( 1 - cos²x)
2 cos²x - 1
Hope this helps you !
cos² x - sin²x / sin²x + cos²x
We know that ,
sin²x + cos²x = 1
so,
cos²x - sin²x /1
we can write ,
sin²x = 1 - cos²x
hence,
cos²x - ( 1 - cos²x)
2 cos²x - 1
Hope this helps you !
Riddhi555:
I'm sorry but that wasn't what i had asked for
u didnt mentione wht u need !
mention*
the question said about cos2x not cos^2x
it was not in terms of square
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