Math, asked by agrimgoel2003, 4 months ago

cos²xdx/cos²x+4sin²x

Answers

Answered by aarushchoudhary59

Step-by-step explanation:

Ssin⁵xcos²xdx

Ssin⁴xcos²xsinxdx; S(sin²x)²cos²xsinxdx; S(1-cos²x)²cos²xsinxdx; u=cosx, du/dx=-sinx; S(1-u²)²u²sinx du/-sinx; -S(u²-2u⁴+u⁶)du = -1/3cos³x + 2/5cos⁵x - 1/7cos⁷x + C

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cos²xdx/cos²x+4sin²x​

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cos²xdx/cos²x+4sin²x