Question

Cos²y/1-siny=1+siny prove left is equal to right

Answer 1

Step-by-step explanation:

here,LHS=RHS

since cos^2Y=1-sin^2Y

Answer 2

Step-by-step explanation:

We know

$\sin {}^{2} ( \gamma ) + \cos {}^{2} ( \gamma ) = 1$

Using this here we obtain

$\frac{ \cos {}^{2} ( \gamma ) }{ 1 - \sin( \gamma ) }$

$\frac{1 - \sin {}^{2} ( \gamma ) }{1 - \sin( \gamma ) }$

We know a^2-b^2=(a-b)(a+b)

Using this formula here we obtain

$\frac{(1 + \sin( \gamma ))(1 - \sin( \gamma ) ) }{1 - \sin( \gamma ) }$

Cancelling 1-siny frok numerator and denominator

We get 1+siny

Hence proved...

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