Question

cos3 x + sec3 x = 2 then sin 6 x + s e c 6 x =

Answer 1

cos³x + sec³x = 2

if cosx and secx both are positive then,
co³x + sec³x ≥2
but it is equal to 2

so, cosx = 1
secx = 1
then this is possible .

hence,
x = 0°

now ,

sin^6x + sec^6x = sin^6(0°) + sec^6(0°)
= 0 + 1 = 1

Answer 2

I think when Cos3x +Sec3x=2
ThenSin6x+Sec6x=4