(cos30 - sin45) divided by (sin²30 + tan²45)
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cos 30= √3/2
sin 45 = 1/√2 =√2/2
√3/2+√2/2= (√3+√2)/2 ....(1)
sin ^2 30= (1/2)^2 =1/4
tan ^2 45= (1)^2=1 .
Thus the required answer is
(√3+√2)/2÷ (1/4+1)
(√3+√2)/2×(4/5)
(√3+√2 )×2/5
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