Question

Cos30°+sec45°÷sin60°

Answer 1

Answer:

$cos \: 30 = \frac{ \sqrt{3} }{2} \\ \\ sec \: 45 = \: \sqrt{2} \\ \\ sin \: 60 = \frac{ \sqrt{3} }{2}$

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cos 30° + sec 45° ÷ sin 60° =

$\frac{ \sqrt{3} }{2} + \frac{ \sqrt{2} }{ \frac{ \sqrt{3} }{2} } \\ = \frac{ \sqrt{3} }{2} + \frac{2 \sqrt{2} }{ \sqrt{3} } \\ = \frac{3 + 4 \sqrt{2} }{2 \sqrt{3} }$

Answer 2

Answer:

Answer:

\begin{gathered}cos \: 30 = \frac{ \sqrt{3} }{2} \\ \\ sec \: 45 = \: \sqrt{2} \\ \\ sin \: 60 = \frac{ \sqrt{3} }{2} \end{gathered}

cos30=

2

3

sec45=

2

sin60=

2

3

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cos 30° + sec 45° ÷ sin 60° =

\begin{gathered} \frac{ \sqrt{3} }{2} + \frac{ \sqrt{2} }{ \frac{ \sqrt{3} }{2} } \\ = \frac{ \sqrt{3} }{2} + \frac{2 \sqrt{2} }{ \sqrt{3} } \\ = \frac{3 + 4 \sqrt{2} }{2 \sqrt{3} } \end{gathered}

2

3

+

2

3

2

=

2

3

+

3

2

2

=

2

3

3+4

2