English, asked by anusuadas00, 8 months ago

cos32°sin20°+cos144°cos2°+sin68°cos56°=0 prove it​

Answers

Answered by Anonymous
41

Answer:

L.H.S = cos32°sin20°+sin68°cos56°+cos144°cos2°

=1/2(2cos32°sin20°+2sin68°cos56°+2cos144°cos2°)

=1/2(sin52°-sin12°+sin124°+sin12°+cos146°+cos142°)

=1/2{sin52°+sin124°+cos(180°-34°)+cos(180°-38°)}

=1/2{sin(90°-38°)+sin(90°+34°)-cos34°-cos38°}

=1/2(cos38°+cos34°-cos34°-cos38°)

=0 R.H.S Proved

Answered by samparai
2

Answer:

thought this can help you

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