Math, asked by adityasingh6434, 9 months ago

Cos38.Cosec52/Cot18.Cot35.Cot60.Cot55.Cot72

Answers

Answered by sbarkha884
0

Answer:

sin52× 1/sin52 /cot18 × tan18× cot35× tan55×cot60

1/cot60

=√3

Answered by SaVu18
0

Answer:root3

Step-by-step explanation:

= cos38°.1/sin52° / cot18°.cot72°.cot55°.cot35°.cot60°

= cos(90-52)°.1/sin52° / cot(90-72)°.cot72°.cot55°.cot(90-55)°.cot60°= sin52°.1/sin52° /tan72°.cot72°.cot55°.tan55°.tan60°

= 1 / tan60°= root3

hope it helps..........

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