Question

cos3theta+costheta upon sin3theta +sintheta

Answer 1

hey mate here is ur answer
$let \: a \: be \: theta \\ \frac{cos \: 3 \: a \: - cos \: a}{sin \: 3 \: a - sin \: a} \\ = \frac{cos \: a( {cos}^{2} a - 1)}{sin \: a \: ( {sin}^{2} a - 1)} \\ = \frac{cos \: a \: ( {sin }^{2} a)}{sin \: a \: ( {cos \: }^{2} a)} \\ \frac{sin \: a}{cos \: a} \\ = tan \: a$
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