Question

cos3theta+sin3theta/cos3theta+sin3theta+cos3theta-sin3theta/cos3theta-sin3theta=2
​

Answer 1

To prove:
(Cos3@+Sin3@/Cos3@+Sin3@)+(Cos3@-Sin3@/Cos3@-Sin3@)=2

Proof:
L•H•S•
[(Cos3@+Sin3@)/(Cos3@+Sin3@)]+[(Cos3@-Sin3@)/(Cos3@-Sin3@)]
[1]+[1]
2
Therefore,LHS=RHS
HENCE PROVED

Hope it will help you!!

Answer 2

Answer:

Explanation:

as in cos3 theta+sin3 theta / cos3theta +sin3theta

the value of numerator and denominator are same therefore we will cut both of them and it will come 1

same is with cos3theta- sin 3 theta / cos3 theta - sin3 theta

it will also come 1

than 1+1 =2 i.e equal to right hand side

RHS = LHS

HENCE PROVED

HOPE IT IS HELPFUL TO YOU