Math, asked by selokar, 10 months ago

cos3theta-sin3theta=(costheta+sintheta)(1-2sin2theta)

Answers

Answered by sandy1816

6

Step-by-step explanation:

cos3A-sin3A

=4cos³A-3cosA-3sinA+4sin³A

=4(cos³A+sin³A)-3(cosA+sinA)

=(cosA+sinA){4(sin²A-sinAcosA+cos²A)-3}

=(sinA+cosA)(4-4sinAcosA-3)

=(sinA+cosA)(1-2.2sinAcosA)

=(cosA+sinA)(1-2sin2A)

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