cos3x+sin5x=0 .Solve for x
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Step-by-step explanation:
cos3x +sin5x =0
cos3x = - sin5x
cos 3x = sin [-5x]
cos3x = cos [ π/2-[-5x]]
cos 3x= cos[π/2+5x]
the solution is π/2 +5x = 2nπ +- 3x
5x +-3x = 2nπ - π/2
8x = 2nπ - π/2 or 2x = 2nπ - π/2
x = nπ/4 - π/16 or x = nπ - π/4
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