cos⁴(45)+sin⁴(45)+2cos²(45)sin²(45)
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SOLUTION :
Given :
4 (sin⁴ 60° + cos⁴ 30°) − 3 (tan² 60° − tan² 45°) + 5 cos² 45°
= 4((√3/2)⁴ + (√3/2)⁴) - 3((√3)²- 1² ) + 5(1/√2)²
[sin 60° = √3/2 , cos 30° = √3/2 , cos 45° =1/√2 , tan 60° = √3, tan 45° = 1]
= 4 (9 / 16) + (9/16)) - 3(3 - 1) + 5 × ½
= 4((9+9)/16) - 3 × 2 + 5/2
= 4 × (18/16 ) - 6 + 5/2
= (18/4) - 6 + 5/2
= 9/2 - 6 + 5/2
= 9/2 + 5/2 - 6
= (9+5) /2 - 6
= 14/2 - 6
= 7 - 6 = 1
4 (sin⁴ 60° + cos⁴ 30°) − 3 (tan² 60° − tan² 45°) + 5 cos² 45° = 1
Hence , 4 (sin⁴ 60° + cos⁴ 30°) − 3 (tan² 60° − tan² 45°) + 5 cos² 45° = 1
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