Math, asked by nos13333, 15 days ago

cos⁴θ + cos²θsin²θ + sin²θ / cos²θ + cos²θ + cos²θsin²θ + sin⁴θ = _____ .​

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Answered by linanguyenyt
2

Answer:

1

Step-by-step explanation:

  cos⁴θ + cos²θsin²θ + sin²θ / cos²θ + cos²θ + cos²θsin²θ + sin⁴θ

=  cos²θ. cos²θ + cos²θsin²θ + sin²θ / cos²θ + cos²θsin²θ + sin²θ.sin²θ

=  cos²θ. ( cos²θ +sin²θ) + sin²θ / cos²θ + (cos²θ + sin²θ) . sin²θ

=  cos²θ . 1 + sin²θ / cos²θ + 1 . sin²θ

=  cos²θ + sin²θ / cos²θ + sin²θ = 1

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