cos40.cosec50=1
please help me this question
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cos40×1/sin50
cos40×1/sin (90-40 )
cos40×1/cos40
=1
cos40×1/sin (90-40 )
cos40×1/cos40
=1
Answered by
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cos40.cosec50=1 LHS: cos (90-50).cosec50 (sin[90theta]=cos theta)= FORMULA sin50.cosec50 1/cosec50×cosec50 (sin theta=1/cosec theta)= FORMULA 1. RHS: 1 LHS=RHS HENCE PROVED. HOPE IT HELPS!!
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