Question

cos45÷sec30+cosec30 answer please​

Answer 1

Answer:

LHS=RHS

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Step-by-step explanation:

(cos 45°)/(sec 30° + cosec 30°)

(cos 45°)/(sec 30° + cosec 30°)`=(1/sqrt2)/(2/sqrt3+2) = (1/sqrt2)/((2+2sqrt3)/sqrt3)`

(cos 45°)/(sec 30° + cosec 30°)`=(1/sqrt2)/(2/sqrt3+2) = (1/sqrt2)/((2+2sqrt3)/sqrt3)``= sqrt3/(sqrt2(2+2sqrt3)) = sqrt3/(2sqrt2+2sqrt6)`

(cos 45°)/(sec 30° + cosec 30°)`=(1/sqrt2)/(2/sqrt3+2) = (1/sqrt2)/((2+2sqrt3)/sqrt3)``= sqrt3/(sqrt2(2+2sqrt3)) = sqrt3/(2sqrt2+2sqrt6)``= (sqrt3(2sqrt6-2sqrt2))/(((2sqrt6)+2sqrt2)(2sqrt6-2sqrt2))`

(cos 45°)/(sec 30° + cosec 30°)`=(1/sqrt2)/(2/sqrt3+2) = (1/sqrt2)/((2+2sqrt3)/sqrt3)``= sqrt3/(sqrt2(2+2sqrt3)) = sqrt3/(2sqrt2+2sqrt6)``= (sqrt3(2sqrt6-2sqrt2))/(((2sqrt6)+2sqrt2)(2sqrt6-2sqrt2))``= (2sqrt3(sqrt6-sqrt2))/((2sqrt6)^2 - (2sqrt2)^2) = (2sqrt3(sqrt6-sqrt2))/(24-8)= (2sqrt3(sqrt6-sqrt2))/16`

(cos 45°)/(sec 30° + cosec 30°)`=(1/sqrt2)/(2/sqrt3+2) = (1/sqrt2)/((2+2sqrt3)/sqrt3)``= sqrt3/(sqrt2(2+2sqrt3)) = sqrt3/(2sqrt2+2sqrt6)``= (sqrt3(2sqrt6-2sqrt2))/(((2sqrt6)+2sqrt2)(2sqrt6-2sqrt2))``= (2sqrt3(sqrt6-sqrt2))/((2sqrt6)^2 - (2sqrt2)^2) = (2sqrt3(sqrt6-sqrt2))/(24-8)= (2sqrt3(sqrt6-sqrt2))/16``= (sqrt18-sqrt6)/8 = (3sqrt2 - sqrt6)/8`

Answer 2

Answer:

Step-by-step explanation:

given :-

cos45 = 1/$\sqrt 2$

sec30 = 2/$\sqrt 3$

cosec30 = 2

according to question,

= (cos45 /sec30) + cosec30

= (1/$\sqrt2$ /2/$\sqrt3$) + 2

= (1/$\sqrt 2$ *$\sqrt3$/2) +2

= ($\sqrt3$/2$\sqrt2$) + 2

= ($\sqrt3$ + 4$\sqrt2$) / 2$\sqrt2$