Math, asked by gutteanjali607644, 4 months ago

cos4A- cos2A = sin4A- sin2A

Answers

Answered by sachinkumar1812

0

Answer:

Solved

Step-by-step explanation:

cos4A−cos2A=sin4A−sin2A

LHS.

=cos2A(1−cos2A)

=cos2Asin2A[∵sin2A+cos2A=1]

RHS

=sin2A(1−sin2A)

=sin2Acos2A[∵sin2A+cos2A=1]

=cos2Asin2A

LHS=RHS

I hope this will be helpful for you...

Good Luck dear

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