Math, asked by soumyahubballi9, 1 day ago

Cos4x + cos3x + cos 2x/ Sin 4x + Sin3x & Sin3x = Cot 3x
​

Answers

Answered by natyavidhanbiswas10
0

sin4x+sin3x+sin2x

----------------------------

cos4x+cos3x+cos2x

=  

(sin4x+sin2x)+sin3x

-------------------------------

(cos4x+cos2x)+cos3x

=  

2sin3xcosx+sin3x

-----------------------------

2cos3xcosx+cos3x

=

sin3x[2cosx+1]

----------------------

cos3x[2cosx+1]

=cot3x

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