Math, asked by karofp12345, 11 months ago

Cos4x(sin5x+3x)=cotx(sin5x-sin3x)

Answers

Answered by rishabh5952

2

Answer:

cot4x(sin5x+3x)=cotx(sin5x-sin3x)

cot4x (2sin4x.cosx)

cos4x/sin4x(2sin4x.cosx)

2cos4x(cosx/sinx)sinx

cotx(2cos4x.sinx)

cotx(sin(4x+x)-sin(4x-x)

cotx(sin5x-sin3x)

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