Math, asked by shivam6622, 1 year ago

cos60°×cos30°+sin60°×sin30°​

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:hope this helps!!

Attachments:
Answered by nain31
4
Given,

 \boxed{ \bold{ cos 60^{ \circ} \times cos^{\circ} 30 + sin 60^{\circ} \times sin 30^{ \circ}}}

We can evaluate it by apllying values of

 cos 60^{ \circ} , cos 30^{ \circ} , sin 60^{\circ} \: and \: sin 30^{ \circ}

Since,

 \boxed{cos 60^{ \circ} = \frac{1}{2}}

 \boxed{cos 30^{ \circ} = \frac{ \sqrt{3}}{2}}

 \boxed{ sin 30^{ \circ} = \frac{1}{2}}

 \boxed{ sin 60^{ \circ} = \frac{ \sqrt{3}}{2}}

On placing values we get

 \frac{1}{2} \times \frac{\sqrt{3}}{2} +\frac{\sqrt{3}}{2} \times \frac{1}{2}

 \frac{\sqrt{3}}{4} +\frac{\sqrt{3}}{4}

 \frac{ 2 \times \sqrt{3}}{4}

 \frac{ \cancel{2} \times \sqrt{3}}{\cancel{4} }

 \frac{\sqrt{3}}{2}

Since,

 \sqrt{3} = 1.732

 \frac{1.732}{2}

 \huge \boxed{ \bold{0.866}}
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