cos6A + sin6A +3sin2A . cos2A = 1
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Step-by-step explanation:
- we will write sin^6 A as (sin^2 A)^3 and cos^6 A as (cos^2 A)^3
- next we will compare with the formula (a+b)^3
- putting the values according to the formula
- we will get the values of "a" and "b"
- next we will put the value of a and b in formula of (a+b)^3
- we get (sin^2 A + cos^2 A)^3
- now we know that sin^2 A + cos^2 A = 1
- so 1^3 = 1
- L.H.S = R.H.S
I HOPE IT HELPS YOU!!
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