Math, asked by kamalsharma42039, 7 months ago

cos6x+cos4x+cos2x=0 find the general solution

Answers

Answered by bourai244

0

Answer:

cos6x+ cos4x + cod2x =0

cos6x+cod2x+cos4x=0

2cos4x cos2x+cos 4x=0

cos4x(2cos2x + 1)=0

cos4x=0. x=π/8

2cos2x+1=0

cos2x= -1/2

cos 2x= cos2π/3

x= 2π/6=π/3

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