Question

cos6x+cos5x+cos4x=0 general solution​

Answer 1

Answer:

Step-by-step explanation:

2Cos5x Cosx - Cos5x = 0

Cos5x(2Cosx -1) = 0

Cos5x = 0                 или            2Cosx -1 = 0

5x = π/2 + πk , k ∈Z                   Cosx = 1/2

x = π/10 + πk/5, k ∈Z                x = +-arcCos1/2 + 2πn , n ∈Z

                                                   x = +-π/3 + 2πn , n ∈Z

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Answer 2

Step-by-step explanation:

see it properly......

1 you have to use formula and than take common okay