Question

(cos70/sin20) +{(cos55.cosec35)/(tan5.tan25.tan65.tan85)}=

Answer 1

according to question :-->

[cos(90-70)/sin 20]=(sin 20 / sin 20)=1 .

[tan (90-5).tan (90-25).tan65 .tan85 ]

cot85.cot65.tan65.tan85. =1/tan85 .1/tan65.×tan65×tan85 =1×1=1 .

so the question 's equation is :--> 1+(cos55.cosec35 ) as 1+(cos55.cosec(90-35)

1+cos square 55.

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