Cos70/sin20+cos57 cosec33-2cos60
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1 is the right answer bro
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Heya,
Given=>
Cos70°/sin20° + cos57°cosec33° - 2cos60°
=> cos(90° - 20°)/sin20° + cos(90° - 33°)cosec33° - 2cos60°
=> sin20°/sin20° + sin33°/sin33° - 2(1/2)
=> 1 + 1 - 1
=> 1. ..... Answer
Hope this helps....:)
Given=>
Cos70°/sin20° + cos57°cosec33° - 2cos60°
=> cos(90° - 20°)/sin20° + cos(90° - 33°)cosec33° - 2cos60°
=> sin20°/sin20° + sin33°/sin33° - 2(1/2)
=> 1 + 1 - 1
=> 1. ..... Answer
Hope this helps....:)
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