cos7x+cos5x/sin7x+sin5x=cotx
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Answer:
Here, we will use the following formulas:
sinA−sinB=2sin(A−B2)cos(A+B2)
cosA+cosB=2cos(A−B2)cos(A+B2)
L.H.S.=cos7x+cos5xsin7x−sin5x
=2cos(7x+5x2)cos(7x−5x2)2cos(7x+5x2)sin(7x−5x2)
=cos(x)sin(x)=cotx=R.H.S.
Step-by-step explanation:
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