Math, asked by viveksingh2464, 6 months ago

cos80/sin10 + cos59×cosec31

Answers

Answered by anindyaadhikari13
31

\star\:\:\:\bf\large\underline\blue{Question:-}

  • Evaluate  \frac{ \cos80\degree}{ \sin10 \degree }  +  \cos59 \degree \times  \cosec31 \degree

\star\:\:\:\bf\large\underline\blue{Solution:-}

  • Before we start, we have to know the formula to solve the problem.
  • Complementary angle formulae are needed while solving this kinds of problems.
  • Two angles are said to be complementary angle if the sum of the angles is 90°.

\star\:\:\:\bf\large\underline\blue{Formula\:To\:Be\:Used:-}

  •  \sin(90 \degree -  \theta)  =  \cos \theta
  • \cos(90\degree-\theta) =\sin\theta

Now, we will solve the problem. Given--

 \frac{ \cos80\degree}{ \sin10 \degree }  +  \cos59 \degree \times  \cosec31 \degree

 =  \frac{ \cos80\degree}{ \sin10 \degree }  +  \cos59 \degree \times    \frac{1}{ \sin31 \degree}

 =  \frac{ \cos80\degree}{ \sin(90  \degree - 80 \degree)}  +   \frac{ \cos59 \degree }{ \sin(90 \degree -59\degree)}

 =  \frac{ \cancel{ \cos80 \degree}}{ \cancel{\cos 80\degree}}  +  \frac{  \cancel{ \cos59 \degree}}{  \cancel{\cos59 \degree}}

 = 1 + 1

 = 2

\star\:\:\:\bf\large\underline\blue{Answer:-}

  • Answer for the problem is 2.
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