Math, asked by pbstate52727, 1 year ago

cos80°÷sin10°+cos59°×cosec31°​

Answers

Answered by srija2507
10

Answer:

2

Step-by-step explanation:

cos80=sin(90-80)=sin10

cos59=sin(90-59)=sin31

cos80/sin10+cos59*cosec31=sin10/sin10+sin31*cosec31

=1+1=2

Answered by joyjit39
6

Step-by-step explanation:

 \frac{ \cos 80}{ \sin10 }  +  \cos59 \times  \cosec31 \\  =   \frac{ \cos(90 - 10) }{ \sin(10) }  +  \frac{ \cos(90 - 31) }{ \sin(31) }  \\  =  \frac{ \sin(10) }{ \sin(10) }  +  \frac{ \sin(31) }{ \sin(31) }   \\  = 1 + 1 = 2

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