Question

(cos84×cot48)/(cot66×cot78)​

Answer 1

Answer:

1 is the answer

Step-by-step explanation:

A=tan6°tan42° and B=cot66°cot78°

A/B=tan6°tan42°tan66°tan78°

Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get

tan42°tan18°tan78°=tan54°...(1)

for x=6° we get

tan54°tan6°tan66°=tan18°...(2)

Eliminating tan54°between (1) and (2)

we get

tan6°tan42°tan66°tan78°=1

Hence A/B=1.