Math, asked by skraut37, 11 months ago

cos9°+ sin9°=√2 sin 54°​

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Answered by abdul9838
3

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 \huge \mathfrak{hola} \\  \\  \small \:hey \: dude \: here \: is \: ur \: ans \\  \\  \huge \bf \: solution \\  \\  \small \bf \: cos \: 9° + sin \: 9° =  \sqrt{2}  \: sin \: 54° \\  \\  \small \bf \: as \: we \: can \: write \\  \\  \bf \: sin \: 9 °+ cos \: 9° =  \sqrt{2} \: sin \: 54° \\  \\  \small \: \bf \:   9°(sin \:  + cos) = cosec \: 45° \times sin \: 54° \\  \\  \small \bf \: 9°(sin + cos) =  \frac{1}{sin \: 45°}  \times sin \: 54° \\  \\  \small \bf \: 9(sin + cos) =  \frac{6}{5}  \\  \\  \small \bf \: sin  \:  + cos =  \frac{6}{5}  \times  \frac{1}{9}  \\  \\  \small \bf \: sin \:  + cos =  \frac{2}{5 \times 3}  \\  \\  \small \bf \: sin \:  + cos =  \frac{2}{15}  \:  \: ans

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Answered by suman682
0

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