cos9B=sinB and B<10° . what's the value of cot5B ?
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Answer:
b=10°
Step-by-step explanation:
cos9b=sinB
by using cos,{90-b} sinB
so cos {99b}=sin (90-9B)
so,sin{90-9b}=sinB
so,90-9b=b,
b=10°
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