Question

cos9x-cos5x/sin17x-sin3x= -sin2x/cos 10x

Answer 1

see the attachment I think it will help you^_^

✴Here , we use two identies i.e

$sin \: c - sin \: d = 2 \: cos\: \frac{(c + d)}{2} sin \frac{(c - d)}{2}$



or,

$cos \: c - cos \: d = - 2sin \frac{(c + d)}{2} sin \frac{(c - d)}{2}$


THANKS ❤^_^


#Nishu HarYanvi ❤

Answer 2

$\huge \red{hello}$

$\purple{here \: is \: u \: r \: ans : }$


$\huge \blue{soni}$