cosA=1/√2•sinB=√3/2 to gyat kijiye sinA cosB+ cosAsinB
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given cosA=1/√2
cosA= cos45°
so A=45°
and sinB=√3/2
sinB=sin60°
so B=60°
Now we have
sinAcosB+cosAsinB
sin45°×cos60°+cos45°×sin60°
1/√2×1/2. + 1/√2×√3/2
1/2√2. + √3/√2
(√2+2√6)/4 is your answer ok
cosA= cos45°
so A=45°
and sinB=√3/2
sinB=sin60°
so B=60°
Now we have
sinAcosB+cosAsinB
sin45°×cos60°+cos45°×sin60°
1/√2×1/2. + 1/√2×√3/2
1/2√2. + √3/√2
(√2+2√6)/4 is your answer ok
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