Question

cosA / 1+ sin A+ 1+ sinA / cos A = 2 sec A​

Answer 1

Step-by-step explanation:

{cosA / (1+ sin A)}+ {(1+ sinA)/cos A} = 2 sec A;

{cos^2 A +(1 + sin A)^2} /{(1+ sinA).cos A)} =2/cos A;

{cos^2 A + sin^2 A+ 1 + 2sin A} / (1+ sinA) =2;

{1 + 1 + 2sin A} / (1+ sinA) =2; (since, cos^2 A + sin^2 A =1)

2{1 + sin A} / (1+ sinA) =2;

2 = 2;

Thus, LHS = RHS.

That's all.