Math, asked by mohit10255, 2 months ago

cosA/1+sinA=1+cosA-sinA/1+cosA+sinA​

Attachments:

Answers

Answered by sandy1816
2

 \frac{1 + cosa - sina}{1 + cosa + sina}  \\  =  \frac{ \frac{1 + cosa - sina}{cosa} }{ \frac{1 + cosa + sina}{cosa} }  \\  =  \frac{seca - tana + 1}{seca + tana + 1}  \\  =  \frac{seca - tana + 1}{(seca + tana) + ( {sec}^{2}a -  {tan}^{2}a)  }  \\  =  \frac{seca - tana + 1}{(seca + tana)(1 + seca - tana)}  \\  =  \frac{1}{seca + tana}  \\  =  \frac{1}{ \frac{1 + sina}{cosa} }  \\  =  \frac{cosa}{1 + sina}

Similar questions