Math, asked by Anonymous, 10 months ago

cosA/1 +sinA =1+ cosA- sinA /1+sinA + cosA

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Answered by sandy1816

0

Step-by-step explanation:

1+cosA-sinA/1+cosA+sinA

devide by cosA in each term

secA-tanA+1/secA+tanA+1

=(secA-tanA+1)/(secA+tanA)+(sec²A-tan²A)

=(secA-tanA+1)/(secA+tanA)(1+secA-tanA)

=1/secA+tanA

=1/(1+sinA/cosA)

=cosA/1+sinA

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