cosA/1+SinA =1-sinA /cosA
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Here is your answer my friend
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Hi !
From LHS .
cos/1+ sinA
Just multiplying by 1- sinA in numerator and denominator .
We get , cosA ( 1-sinA)/(1+sinA)(1-sinA)
=> cosA ( 1-sinA)/(1-sin²A)
=> cosA (1-sinA)/cos²A
=> (1-sinA)/cosA RHS
LHS = RHS PROVED
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Hope it's helpful
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