Question

Cosa/1+sina = 1 – sina/cosa

Answer 1

Answer:

CosA/1+sinA

= CosA/(1+sinA)  * 1-sinA/1-sinA  

=CosA(1-sinA)/(1-sin²A)

=CosA (1-sinA)/Cos²A

=1-sinA/CosA

Hence proved L.H.S=R.H.S

Explanation:

Answer 2

Answer:

LHS =cosA/(1+sinA) +(1+sinA)/cosA

={cos²A +(1+sinA)²}/cosA.(1+sinA)

={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)

use sin²∅ +cos²∅ =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA = RHS