cosA/1+sinA +1+sinA/cosA =2sec
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Step-by-step explanation:
(cosA/1+sinA) +(1+sinA/cosA)
=> cos²A + (1+sinA)²/ cosA(1+sinA). (Taking LCM)
=> cos²A+ 1+ sin²A+ 2sinA/ cosA(1+sinA)
=>2+ 2sinA/ cosA(1+sinA). (Sin²A + Cos²A= 1)
=> 2(1+sinA)/cosA(1+sinA)
=> 2/cosA
=>2× 1/cosA
=> 2secA
NeverMind11:
thanks
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