Question

(cosA/1+sinA)+(1+sinA/cosA)=2secA​

Answer 1

Answer:

i hope you are satisfied with my solution

Answer 2

Step-by-step explanation:

(cosA/1+sinA)+(1+sinA/cosA)=2secA

(cosA*cosA + (1+sinA) *(1+sinA))/ ((1+sinA) * cosA)

cos^2 A + 1 + 2sinA + Sin^2 A / ((1+sinA) *cosA)

cos^2 A + Sin^2 A = 1

so, 1 + 1 + 2sinA / ((1+sina) * cosA)

2(1+sinA)/((1+sinA) * cosA)

cancel 1+sinA

2/cosA

1/cosA = secA

so, 2secA