(CosA/1+sinA)+(1+SINa/cosA)=2secA
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Answer:
cos
A
1
+
sin
A
+
1
+
sin
A
cos
A
=
(
cos
A
⋅
cos
A
)
+
(
1
+
sin
A
)
(
1
+
sin
A
)
cos
A
(
1
+
sin
A
)
=
cos
2
A
+
1
+
2
sin
A
+
sin
2
A
cos
A
(
1
+
sin
A
)
=
2
+
2
sin
A
cos
A
(
1
+
sin
A
)
(as,
cos
2
A
+
sin
2
A
=
1
)
=
2
(
1
+
sin
A
)
cos
A
(
1
+
sin
A
)
=
2
cos
A
=
2
sec
A
Step-by-step explanation:
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