Question

cosA/1+sinA + 1+sinA/cosA=2secA

pls help plss​

Answer 1

Step-by-step explanation:

cosA/(1 + sinA) + (1 + sinA)/cosA

     Divide and multiply the term cosA/(1 + sinA) with 1 - sinA:

cosA(1-sinA)/(1+sinA)(1-sinA) + (1+sinA)/cosA

cosA(1-sinA)/(1 - sin²A) + (1+sinA)/cosA

cosA(1-sinA)/cos²A + (1+sinA)/cosA

(1-sinA)/cosA + (1+sinA)/cosA

(1-sinA + 1+sinA)/cosA

(1+1)/cosA

2/cosA  = 2*1/cosA

2secA         Proved

Answer 2

Answer:

ur ans is in the pic

hope u understand...