Question

cosA/1+sinA + 1+sinA/cosA=2sinA​

Answer 1

Hey friend (^_^)

Here is your answer

LHS :

=(1/sinA+cosA)+(1/sinA-cosA)

TAKING LCM

=(sinA-cosA+sinA+cosA)/(sin²A-cos²A)

[Using sin²A=1-cos²A]

=2sinA/(1-cos²A-cos²A)

=2sinA/(1-2cos²A)

=RHS