Math, asked by manjuprashanth864, 9 months ago

cosa+1_sina/cosa-1+sina=1+(cosa/sina)​

Answers

Answered by sandy1816
2

Step-by-step explanation:

cosA+1-sinA/cosA-1+sinA

devide each term by sinA

=cotA+cosecA-1/cotA-cosecA+1

=(cotA+cosecA)-(cosec²A-cot²A)/ cotA-cosecA+1

=(cotA+cosecA)(1-cosecA+cotA)/ (cotA-cosecA+1)

=cotA+cosecA

=(cosA/sinA)+(1/sinA)

=(1+cosA)/sinA

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